25x^2+60x+36=30

Solution for 25x^2+60x+36=30 equation:

25x^2+60x+36=30

We move all terms to the left:

25x^2+60x+36-(30)=0

We add all the numbers together, and all the variables

25x^2+60x+6=0

a = 25; b = 60; c = +6;
Δ = b2-4ac
Δ = 602-4·25·6
Δ = 3000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3000}=\sqrt{100*30}=\sqrt{100}*\sqrt{30}=10\sqrt{30}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-10\sqrt{30}}{2*25}=\frac{-60-10\sqrt{30}}{50}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+10\sqrt{30}}{2*25}=\frac{-60+10\sqrt{30}}{50}
$